*** Problems in this lecture due 05/03/2026 at 23:59 ***
Let be an algebra. In Week I of Math 202B, we saw that subalgebras of
always come in pairs: associated to each subalgebra
is its centralizer
the set of elements in
which commute with every element in
We used this fact to characterize maximal abelian subalgebras of
as precisely those commutative subalgebras
which are equal to their own centralizer,
A problem we might have already posed back then is to characterize those subalgebras for which
is commutative. Today, we will address this question in the case where
is the convolution algebra of a finite group
and
is the convolution algebra of a subgroup
viewed as the subalgebra of
spanned by the orthogonal set
For any element , let
denote its image in the regular representation of
Furthermore, let
be a set indexing isomorphism classes of irreducible unitary representations of
, and for each
let
denote the image of
in a representative
of the isomorphism class indexed by
Problem 12.1. Prove that if and only if
for each
and every
Let be arbitrary but fixed. Thanks to Problem 12.1, understanding when
is commutative reduces to understanding when the algebra
is commutative. If it were the case that
was an irreducible representation of
this would be extremely easy, since then Schur’s Lemma would force
to be one-dimensional. However,
is an irreducible representation of
and there is no reason why it should be irreducible as a representation of the subalgebra
So, we will have to understand what conditions would cause
to be commutative by analyzing the behavior of
under restriction from
to
Let be a set parameterizing isomorphism classes of irreducible unitary representations of
(or equivalently irreducible linear representations of
). Consider the isotypic decomposition of
as a representation of
, which has the form
where two summands and
are isomorphic unitary representations of
if and only if
In finer detail, each
further decomposes as
where and
are isomorphic irreducible unitary representations of
and
is a positive integer.
Problem 12.2. Prove that if , then
maps each
-isotypic component
of
into itself.
Problem 12.2 allows us to focus on intertwiners for a fixed
. Each such operator may be visualized as a block matrix
where Now, since
and
are irreducible unitary representations of
Schur’s Lemma tells us that
is one-dimensional, so in fact each block
can be identified with a scalar
and
itself can be identified with an
matrix of complex numbers. We thus have an algebra isomorphism
which is important as a standalone fact, but also tells us that is commutative if and only if
for each
We have thus established the following theorem.
Theorem 12.1. The centralizer is a commutative subalgebra of
if and only if the restriction of each irreducible unitary representation of
to a unitary representation of
is multiplicity free: for every
we have